Optimal. Leaf size=127 \[ \frac{\text{Ei}\left (2 \log \left (c \left (b x^2+a\right )\right )\right )}{b^2 c^2}-\frac{a \text{li}\left (c \left (b x^2+a\right )\right )}{4 b^2 c}-\frac{a \left (a+b x^2\right )}{4 b^2 \log \left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{4 b \log ^2\left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{2 b \log \left (c \left (a+b x^2\right )\right )} \]
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Rubi [A] time = 0.170153, antiderivative size = 127, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 9, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.562, Rules used = {2454, 2400, 2399, 2389, 2298, 2390, 2309, 2178, 2297} \[ \frac{\text{Ei}\left (2 \log \left (c \left (b x^2+a\right )\right )\right )}{b^2 c^2}-\frac{a \text{li}\left (c \left (b x^2+a\right )\right )}{4 b^2 c}-\frac{a \left (a+b x^2\right )}{4 b^2 \log \left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{4 b \log ^2\left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{2 b \log \left (c \left (a+b x^2\right )\right )} \]
Antiderivative was successfully verified.
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Rule 2454
Rule 2400
Rule 2399
Rule 2389
Rule 2298
Rule 2390
Rule 2309
Rule 2178
Rule 2297
Rubi steps
\begin{align*} \int \frac{x^3}{\log ^3\left (c \left (a+b x^2\right )\right )} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{x}{\log ^3(c (a+b x))} \, dx,x,x^2\right )\\ &=-\frac{x^2 \left (a+b x^2\right )}{4 b \log ^2\left (c \left (a+b x^2\right )\right )}+\frac{1}{2} \operatorname{Subst}\left (\int \frac{x}{\log ^2(c (a+b x))} \, dx,x,x^2\right )+\frac{a \operatorname{Subst}\left (\int \frac{1}{\log ^2(c (a+b x))} \, dx,x,x^2\right )}{4 b}\\ &=-\frac{x^2 \left (a+b x^2\right )}{4 b \log ^2\left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{2 b \log \left (c \left (a+b x^2\right )\right )}+\frac{a \operatorname{Subst}\left (\int \frac{1}{\log ^2(c x)} \, dx,x,a+b x^2\right )}{4 b^2}+\frac{a \operatorname{Subst}\left (\int \frac{1}{\log (c (a+b x))} \, dx,x,x^2\right )}{2 b}+\operatorname{Subst}\left (\int \frac{x}{\log (c (a+b x))} \, dx,x,x^2\right )\\ &=-\frac{x^2 \left (a+b x^2\right )}{4 b \log ^2\left (c \left (a+b x^2\right )\right )}-\frac{a \left (a+b x^2\right )}{4 b^2 \log \left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{2 b \log \left (c \left (a+b x^2\right )\right )}+\frac{a \operatorname{Subst}\left (\int \frac{1}{\log (c x)} \, dx,x,a+b x^2\right )}{4 b^2}+\frac{a \operatorname{Subst}\left (\int \frac{1}{\log (c x)} \, dx,x,a+b x^2\right )}{2 b^2}+\operatorname{Subst}\left (\int \left (-\frac{a}{b \log (c (a+b x))}+\frac{a+b x}{b \log (c (a+b x))}\right ) \, dx,x,x^2\right )\\ &=-\frac{x^2 \left (a+b x^2\right )}{4 b \log ^2\left (c \left (a+b x^2\right )\right )}-\frac{a \left (a+b x^2\right )}{4 b^2 \log \left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{2 b \log \left (c \left (a+b x^2\right )\right )}+\frac{3 a \text{li}\left (c \left (a+b x^2\right )\right )}{4 b^2 c}+\frac{\operatorname{Subst}\left (\int \frac{a+b x}{\log (c (a+b x))} \, dx,x,x^2\right )}{b}-\frac{a \operatorname{Subst}\left (\int \frac{1}{\log (c (a+b x))} \, dx,x,x^2\right )}{b}\\ &=-\frac{x^2 \left (a+b x^2\right )}{4 b \log ^2\left (c \left (a+b x^2\right )\right )}-\frac{a \left (a+b x^2\right )}{4 b^2 \log \left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{2 b \log \left (c \left (a+b x^2\right )\right )}+\frac{3 a \text{li}\left (c \left (a+b x^2\right )\right )}{4 b^2 c}+\frac{\operatorname{Subst}\left (\int \frac{x}{\log (c x)} \, dx,x,a+b x^2\right )}{b^2}-\frac{a \operatorname{Subst}\left (\int \frac{1}{\log (c x)} \, dx,x,a+b x^2\right )}{b^2}\\ &=-\frac{x^2 \left (a+b x^2\right )}{4 b \log ^2\left (c \left (a+b x^2\right )\right )}-\frac{a \left (a+b x^2\right )}{4 b^2 \log \left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{2 b \log \left (c \left (a+b x^2\right )\right )}-\frac{a \text{li}\left (c \left (a+b x^2\right )\right )}{4 b^2 c}+\frac{\operatorname{Subst}\left (\int \frac{e^{2 x}}{x} \, dx,x,\log \left (c \left (a+b x^2\right )\right )\right )}{b^2 c^2}\\ &=\frac{\text{Ei}\left (2 \log \left (c \left (a+b x^2\right )\right )\right )}{b^2 c^2}-\frac{x^2 \left (a+b x^2\right )}{4 b \log ^2\left (c \left (a+b x^2\right )\right )}-\frac{a \left (a+b x^2\right )}{4 b^2 \log \left (c \left (a+b x^2\right )\right )}-\frac{x^2 \left (a+b x^2\right )}{2 b \log \left (c \left (a+b x^2\right )\right )}-\frac{a \text{li}\left (c \left (a+b x^2\right )\right )}{4 b^2 c}\\ \end{align*}
Mathematica [A] time = 0.12011, size = 87, normalized size = 0.69 \[ -\frac{-\frac{4 \text{Ei}\left (2 \log \left (c \left (b x^2+a\right )\right )\right )}{c^2}+\frac{a \text{Ei}\left (\log \left (c \left (b x^2+a\right )\right )\right )}{c}+\frac{\left (a+b x^2\right ) \left (\left (a+2 b x^2\right ) \log \left (c \left (a+b x^2\right )\right )+b x^2\right )}{\log ^2\left (c \left (a+b x^2\right )\right )}}{4 b^2} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.088, size = 0, normalized size = 0. \begin{align*} \int{\frac{{x}^{3}}{ \left ( \ln \left ( c \left ( b{x}^{2}+a \right ) \right ) \right ) ^{3}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{b^{2} x^{4}{\left (2 \, \log \left (c\right ) + 1\right )} + a b x^{2}{\left (3 \, \log \left (c\right ) + 1\right )} + a^{2} \log \left (c\right ) +{\left (2 \, b^{2} x^{4} + 3 \, a b x^{2} + a^{2}\right )} \log \left (b x^{2} + a\right )}{4 \,{\left (b^{2} \log \left (b x^{2} + a\right )^{2} + 2 \, b^{2} \log \left (b x^{2} + a\right ) \log \left (c\right ) + b^{2} \log \left (c\right )^{2}\right )}} + \int \frac{4 \, b x^{3} + 3 \, a x}{2 \,{\left (b \log \left (b x^{2} + a\right ) + b \log \left (c\right )\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.05819, size = 325, normalized size = 2.56 \begin{align*} -\frac{b^{2} c^{2} x^{4} + a b c^{2} x^{2} +{\left (a c \logintegral \left (b c x^{2} + a c\right ) - 4 \, \logintegral \left (b^{2} c^{2} x^{4} + 2 \, a b c^{2} x^{2} + a^{2} c^{2}\right )\right )} \log \left (b c x^{2} + a c\right )^{2} +{\left (2 \, b^{2} c^{2} x^{4} + 3 \, a b c^{2} x^{2} + a^{2} c^{2}\right )} \log \left (b c x^{2} + a c\right )}{4 \, b^{2} c^{2} \log \left (b c x^{2} + a c\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{3 a x}{\log{\left (a c + b c x^{2} \right )}}\, dx + \int \frac{4 b x^{3}}{\log{\left (a c + b c x^{2} \right )}}\, dx}{2 b} + \frac{- a b x^{2} - b^{2} x^{4} + \left (- a^{2} - 3 a b x^{2} - 2 b^{2} x^{4}\right ) \log{\left (c \left (a + b x^{2}\right ) \right )}}{4 b^{2} \log{\left (c \left (a + b x^{2}\right ) \right )}^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.28478, size = 190, normalized size = 1.5 \begin{align*} -\frac{a c{\rm Ei}\left (\log \left ({\left (b x^{2} + a\right )} c\right )\right ) - \frac{{\left (b c x^{2} + a c\right )} a c}{\log \left ({\left (b x^{2} + a\right )} c\right )} - \frac{{\left (b c x^{2} + a c\right )} a c}{\log \left ({\left (b x^{2} + a\right )} c\right )^{2}} + \frac{2 \,{\left (b c x^{2} + a c\right )}^{2}}{\log \left ({\left (b x^{2} + a\right )} c\right )} + \frac{{\left (b c x^{2} + a c\right )}^{2}}{\log \left ({\left (b x^{2} + a\right )} c\right )^{2}} - 4 \,{\rm Ei}\left (2 \, \log \left ({\left (b x^{2} + a\right )} c\right )\right )}{4 \, b^{2} c^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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